Today we are going to solve HackerRank Day 21 : Generics 30 days of code solution in C++ & Java.
Objective
Today we’re discussing Generics; be aware that not all languages support this construct, so fewer languages are enabled for this challenge. Check out the Tutorial tab for learning materials and an instructional video!
Task
Write a single generic function named printArray; this function must take an array of generic elements as a parameter (the exception to this is C++, which takes a vector). The locked Solution class in your editor tests your function.
Note: You must use generics to solve this challenge. Do not write overloaded functions.
Input Format
The locked Solution class in your editor will pass different types of arrays to your printArray function.
Constraints
- You must have exactly 1 function named printArray.
Output Format
Your printArray function should print each element of its generic array parameter on a new line.
HackerRank Day 21 : Generics 30 days of code solution
Generics HackerRank Solution in C++
#include <iostream>
#include <vector>
#include <string>
using namespace std;
// Write your code here
template <class T>
void printArray(vector<T> i)
{
for(int j=0;j<i.size();j++)
cout<<i[j]<<endl;
}
int main() {
int n;
cin >> n;
vector<int> int_vector(n);
for (int i = 0; i < n; i++) {
int value;
cin >> value;
int_vector[i] = value;
}
cin >> n;
vector<string> string_vector(n);
for (int i = 0; i < n; i++) {
string value;
cin >> value;
string_vector[i] = value;
}
printArray<int>(int_vector);
printArray<string>(string_vector);
return 0;
}Generics HackerRank Solution in Java
import java.util.*;
class Printer <T> {
public static <E> void printArray(E[] generic){
for(E element: generic){
System.out.println(element);
}
}
}
public class Generics {
public static void main(String args[]){
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
Integer[] intArray = new Integer[n];
for (int i = 0; i < n; i++) {
intArray[i] = scanner.nextInt();
}
n = scanner.nextInt();
String[] stringArray = new String[n];
for (int i = 0; i < n; i++) {
stringArray[i] = scanner.next();
}
Printer<Integer> intPrinter = new Printer<Integer>();
Printer<String> stringPrinter = new Printer<String>();
intPrinter.printArray( intArray );
stringPrinter.printArray( stringArray );
if(Printer.class.getDeclaredMethods().length > 1){
System.out.println("The Printer class should only have 1 method named printArray.");
}
}
}NEXT : HackerRank Day 22 : Binary Search Trees 30 days of code solution
30 Days of Code HackerRank Solutions List – Day 0 to Day 29
Read More –
